-35=-16t^2+50t+35

Solution for -35=-16t^2+50t+35 equation:

-35=-16t^2+50t+35

We move all terms to the left:

-35-(-16t^2+50t+35)=0

We get rid of parentheses

16t^2-50t-35-35=0

We add all the numbers together, and all the variables

16t^2-50t-70=0

a = 16; b = -50; c = -70;
Δ = b2-4ac
Δ = -502-4·16·(-70)
Δ = 6980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6980}=\sqrt{4*1745}=\sqrt{4}*\sqrt{1745}=2\sqrt{1745}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{1745}}{2*16}=\frac{50-2\sqrt{1745}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{1745}}{2*16}=\frac{50+2\sqrt{1745}}{32}
$